All categories

2 years ago

How many teams haven't won a super bowl A. 2 B. 12 C. None D. 3

Mathematics

1 answer:

m_a_m_a [10]2 years ago

4 0

Answer:

B. 12

12 teams have never won a Super Bowl :))))

You might be interested in

Who else hates it when they take down your questions?

True [87]

Lol ikr

Some people are lucky their question stays for more than a week. And their question is useless

Unfair. Always

8 0

3 years ago

How many terms are in the expression 5a+1? 1 4 3 2

Studentka2010 [4]

Answer:

I think the answer is 2

Step-by-step explanation:

7 0

2 years ago

Brainliest AGAIN, lol, help quickly!

Neko [114]

Answer:

Step-by-step explanation:

divide 4 and 12 by 4 and get 1/3

7 0

2 years ago

Read 2 more answers

I GIVE BRAINLIEST FOR ANSWERS AND EXPLANATION

irina1246 [14]

Answer:

18.1

Step-by-step explanation:

You can use the c = b/cos(a) which when subsituted gives u c= 16/cos(28) which when u solve gives u 18.12112

3 0

3 years ago

Read 2 more answers

50 points!!! Someone help pls, I can’t understand it and it’s due tomorrow :c

liraira [26]

${\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}$

$\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}$

❍ Arrange the given data in order either in ascending order or descending order.

2, 3, 4, 7, 9, 11

❍ Number of terms in data [n] = 6 which is even.

As we know,

$\star \: \sf Median_{(when \: n \: is \: even)} = {\underline{\boxed{\sf{\purple{ \dfrac{ { \bigg (\dfrac{n}{2} \bigg)}^{th}term +{ \bigg( \dfrac{n}{2} + 1 \bigg)}^{th} term } {2} }}}}}$

$\\$

$\sf Median_{(when \: n \: is \: even)} ={ \dfrac{ { \bigg (\dfrac{6}{2} \bigg)}^{th}term +{ \bigg( \dfrac{6}{2} + 1 \bigg)}^{th} term } {2} }$

$\\$

$\sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \dfrac{6 + 2}{2} \bigg)}^{th} term } {2} }$

$\\$

$\sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \cancel{ \dfrac{8}{2}} \bigg)}^{th} term } {2} }$

$\\$

$\sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ 4}^{th} term } {2} }$

• Putting,

3rd term as 4 and the 4th term as 7.

$\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 4 + 7 } {2} }$

$\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 11} {2} }$

$\longrightarrow \: \sf Median_{(when \: n \: is \: even)} = \purple{5.5}$

$\\$

${\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}$

$\star\:{\underline{\underline{\sf{\red{Solution:}}}}}$

❍ Arrange the given data in order either in ascending order or descending order.

1, 2, 3, 4, 5, 6, 7

❍ Number of terms in data [n] = 7 which is odd.

As we know,

$\star \: \sf Median_{(when \: n \: is \: odd)} = {\underline{\boxed{\sf{\red{ { \bigg( \frac{n + 1}{2} \bigg)}^{th} term}}}}}$

$\\$

$\sf Median_{(when \: n \: is \: odd)} = {{ \bigg(\dfrac{ 7 + 1 } {2} \bigg) }}^{th} term$

$\\$

$\sf Median_{(when \: n \: is \: odd)} = { \bigg(\cancel{\dfrac{8}{2}} \bigg)}^{th} term$

$\\$

$\sf Median_{(when \: n \: is \: odd)} ={ 4}^{th} term$

• Putting,

4th term as 4.

$\longrightarrow \: \sf Median_{(when \: n \: is \: odd)} = \red{ 4}$

$\\$

${\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}$

$\star\:{\underline{\underline{\sf{\green{Solution:}}}}}$

The frequency distribution table for calculations of mean :

$\begin{gathered}\begin{array}{|c|c|c|c|c|c|c|} \hline \rm x_{i} &\rm 3&\rm 1&\rm 7&\rm 4&\rm 6&\rm 2 \rm \\ \hline\rm f_{i} &\rm 4&\rm 6&\rm 2&\rm 2 & \rm 1&\rm 1 \\ \hline \rm f_{i}x_{i} &\rm 12&\rm 6&\rm 14&\rm 8&\rm 6&\rm \rm 2 \\ \hline \end{array} \\ \end{gathered}$