It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
Answer:
8x + 2y.
Step-by-step explanation:
8 . x . 2 . y = 16xy = 16yx
Considering there is not much information my best guess would be 175-28x
Answer:
A. I only
I. y>2x
Step-by-step explanation:
I. y>2x
He sold x bicycles last week and y bicycles this week, this week, he earned more than twice as much as he did last week. Therefore more than twice means greater than 2 x or
y>2x
II. y>x This is not true because y could be greater than x and less than twice of x (2x)
III. y>3 This is also not true because the least he would be earning would be $ 20 and he could get earn greater than 3 and less than $ 20 which would again be contradictory to the given statement
