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3 years ago

PLZ HELP FAST WILL GIVE BRAINLIEST!!!

2 answers:

7 0

Height = {16, 17, 14, 18, 20, 16, 18, 17}
= {14, 16, 16, 17, 17, 18, 18, 20}

Mean height = (14+16+16+17+17+18+18+20)/8 = 136/8 = 17 inches

Median height = (17+17)/2 = 17 inches

Hope it helps!

defon3 years ago

3 0

The answer is going to be 12.9 and the median height will be 16.5 hope that helped

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F=(2xy +z³)i + x³j + 3xz²k find a scalar potential and work done in moving an object in the field from (1,-2,1) to (3,1,4)

Alex73 [517]

Step-by-step explanation:

Given:

$\textbf{F} = (2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}$

This field will have a scalar potential $\varphi$ if it satisfies the condition $\nabla \times \textbf{F}=0$ . While the first x- and y- components of $\nabla \times \textbf{F}$ are satisfied, the z-component doesn't.

$(\nabla \times \textbf{F})_z = \left(\dfrac{\partial F_y}{\partial x} - \dfrac{\partial F_x}{\partial y} \right)$

$\:\:\:\:\:\:\:\:\: = 3x^2 - 2x \ne 0$

Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector $\vec{\textbf{r}}$ as

$\vec{\textbf{r}} = x \hat{\textbf{i}} + y \hat{\textbf{j}} + z \hat{\textbf{k}}$

and its differential is

$\textbf{d} \vec{\textbf{r}} = dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}}$

The work done then is given by

$\displaystyle \oint_c \vec{\textbf{F}} • \textbf{d} \vec{\textbf{r}} = \int ((2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}) • (dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}})$

$\displaystyle = (x^2y + xz^3) + x^3y + xz^3|_{(1, -2, 1)}^{(3, 1, 4)}$

$= 422$

5 0

3 years ago

6 + ( 2 − 3 ( 4 ) ) + 1 /( 5 ) ( 2 ) − 4

tankabanditka [31]

6 + (2 - 3 (4) )+1 / (5) (2) - 4 = -1 /2

Step-by-step explanation:

6 + (2 - 3 (4) )+1 / (5) (2) - 4

Using the BODMAS rule, we can simplify the expression in the following way, like, we have to do the operation inside the brackets first, then division, multiplication, addition and then subtraction.

= 6 + (2 - 3 (4) )+1 / (5) (2) - 4 [operation inside the brackets]

= 6 + (2 - 12) )+1 / (5) (2) - 4

= 6 + (-10) )+1 / (10) - 4

= 6 + 1 -10 / (10) - 4

= 7 - 10/ 6

= -3 / 6

= -1/2

4 0

2 years ago

Solye for x. 8(x + 1) - 3[X + 4) = 7(2 - x)

kramer

Answer:

3/2

Step-by-step explanation:

distribute 8,-3,7

4 0

2 years ago

Please help with this

gladu [14]

Answer: Y=-3x+5
Explanation:

6 0

2 years ago

PLEASE HELP IM ON A TIME LIMIT :(

Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

$\sqrt{ {1}^{2} + {1}^{2} }$

$= \sqrt{2}$

$= \sqrt{ {(3 - 5)}^{2} + {(1 + 1}^{2} } \\ = \sqrt{ {( - 2)}^{2} + {(2)}^{2} } \\ = \sqrt{4 + 4} \\ = \sqrt{8} \\ = 2 \sqrt{2}$

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

scale factor = AB/DE

= 2

It's been reflected across the Y-axis

moved thru the translation of 3 units towards the right of positive x- axis 

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

7 0

2 years ago