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scZoUnD [109]
3 years ago
5

Solve the following quadratic equation for all values of x in simplest form. 3(4x + 1)2 – 37 = 5

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

Step-by-step explanation:

Add 37 to both sides (to combine like terms):

3(4x + 1)^2 = 42

Reduce this by dividing both sides by 3:

(4x + 1)^2 = 14

Taking the square root of both sides results in:

4x + 1 = ± √14, or

4x = -1 ± √14

Solve for x by dividing both sides by 4:

       -1 ± √14

x = ----------------

              4

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Step-by-step explanation:

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cricket20 [7]

Answer:

Sometimes true. It may be true at times if x or y equal each other, but if they do not equal each other it is not true

Step-by-step explanation:

We are given two expressions:  x -3 and y  - 3

Here x and y are two different variables.

These expressions are equal, when the value of x and the value of y are equal.

x - 3 = y -3 if x = y.

Therefore, the two expressions have the same value in sometimes.

That is, when x = y, then the value of two expressions are the same.

Example.

If x = 2 and y = 2, then

x - 3 = y - 3

2 - 3 = 2 - 3

-1 = -1

If they have different values, for x =  2 and y = 3

x - 3 = y - 3

2 - 3 = 3 -3

-1 = 0

Which is not true.

Therefore, the answer is sometimes.

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-128%7D%20x%5E%7B6%7D%20y%5E%7B5%7D" id="TexFormula1" title="\sqrt[3]{-128} x
Jobisdone [24]

Answer: the imagine shown below is ur answer :)

Step-by-step explanation:

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