Answer:
0.0903
Step-by-step explanation:
Given that :
The mean = 1450
The standard deviation = 220
sample mean = 1560



P(X> 1560) = P(Z > 0.5)
P(X> 1560) = 1 - P(Z < 0.5)
From the z tables;
P(X> 1560) = 1 - 0.6915
P(X> 1560) = 0.3085
Let consider the given number of weeks = 52
Mean
= np = 52 × 0.3085 = 16.042
The standard deviation =
The standard deviation = 
The standard deviation = 3.3306
Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.
Then;
Pr ( Y > 20) = P( z > 20)


From z tables
P(Y > 20)
0.0903
Answer:
One tailed
To conclude if there is an increase in the mean gas mileage due to new type of tire.
Step-by-step explanation:
We are given the following in the question:
The manufacture wants to compare increase in the mean gas mileage.
Population mean = 32 miles per gallon
Thus, the manufacture could carry a hypothesis test to compare mean.
A one tailed test (z-test or t-test) based on the information can be used to compare the increase in mean.
Thus,
The automotive manufacturer should perform a one tailed hypothesis test to conclude if there is an increase in the mean gas mileage due to new type of tire.
ANSWER:
mean:47.8
mode:57
median:45
37, 38, 43, 45, 57, 57, 58