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tiny-mole [99]
3 years ago
14

7th grade work help please will give brainliest:)

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0

Answer: 67.27

Step-by-step explanation:

7.1 x 7.1 for the square = 50.41

7.1 divided by 2 = 3.55

3.55 x 4.75= 16.86

Normally here you would divide by 2, but you don’t need two because there is 2 triangles that are the same

Add the 50.41 and the 16.86 and you have your answer!

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H(x) = x3 + 7<br> Determine whether the function is one-to-one.
zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

  • passes the vertical line test to make sure it is indeed a function, and
  • also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

h\left(x\right)\:=\:x^3\:+\:7

Have a look at the attached graph.

  • The red portion represents the graph of the function h\left(x\right)\:=\:x^3\:+\:7.
  • The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is indeed a function.
  • The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0
4 years ago
Which equation represents the line that is parallel to segment RS in the triangle below and passes through point T?
mestny [16]

Answer:

y  = \frac{1}{2}x +4

Step-by-step explanation:

Given:

R = (0,0)

S= (8,4)

T = (-2,3)

First, we have that the line is parallel to RS.

This means that the line has the same slope as RS and the slope of RS is calculated as follows:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{4-0}{8-0}

m = \frac{4}{8}

m = \frac{1}{2}

So, the line has a slope of m = \frac{1}{2}

Next, we have that the line passes through T = (-2,3).

The equation of the line is then calculated using the following formula

y - y_1 = m(x - x_1)

y - 3 = \frac{1}{2}(x - (-2))

y - 3 = \frac{1}{2}(x +2)

Open bracket

y - 3 = \frac{1}{2}x +1

Make y the subject

y  = \frac{1}{2}x +1+3

y  = \frac{1}{2}x +4

8 0
3 years ago
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