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3 years ago

I need help im confuse

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

Answer:

B. 12b $\leq$ 17

Step-by-step explanation:

< means less than

> means greater than

$\leq$ means less than or equal to

$\geq$ means greater than or equal to.

hope this helps.

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HELP PLEASE ILL GIVE THE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!

kirill115 [55]

Answer:

Step-by-step explanation:

I don't know how to explain it, but i did the math and that is what i got, i'm sorry if it is incorrect. Hope this helps :3

3 0

3 years ago

A lunch box costs $4.50 plus sales tax. After sales tax, the lunch box is $4.86. What is the sales tax rate?

Alborosie

8 percent (C)

To find 1% you divide 4.50 by 100, which is 0.045.

Then you have to find what is added on.
4.86-4.50 is .36

Now you divide .36 by 0.045. An easier way to do this is 360 divided by 45. This equals 8.

Hope this helped

3 0

3 years ago

How do you multiplies fractions?

Lostsunrise [7]

Just multiply straight across. (Left to right.)

Multiply both numbers on the top then both on the bottom. Then just simplify.

An example is 1/2 x 3/4 = 3/6 then 1/2

7 0

4 years ago

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Line AB

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Line BC

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Line AC

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

Perimeter of Triangle ABC

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago

Help me please thanks in advance

Xelga [282]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

From up to down ;

_________________________________

The first box :

$f(n) = 3. ({2})^{n - 1}$

The second box :

$f(n) = 2. ({4})^{n - 1}$

The third box :

$f(n) = 2. ({6})^{n - 1}$

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4 0

3 years ago