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aev [14]
3 years ago
15

An arc of length 8 inches. Is intercepted by a central angle in a circle with a radius of 3 inches. What is the measurement of t

he angle. Round your answer to the nearest 10th.
Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

the answer is 12

Step-by-step explanation:

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What is the product? startfraction x squared minus 16 over 2 x 8 endfraction times startfraction x cubed minus 2 x squared x ove
melamori03 [73]

The product of the given expression is \frac{x(x-1)(x-4)}{2(x+4)} OR \frac{x(x^{2} -5x+4)}{2x+8} OR \frac{x^{3} -5x^{2} +4x}{2x+8}

<h3>Simplifying fractions </h3>

From the question, we are to determine the product of the given expressions

The given expressions are

\frac{x^{2} - 16}{2x+8}\times \frac{x^{3}-2x^{2} +x}{x^{2} +3x-4}

\frac{(x+4)(x-4)}{2(x+4)}\times \frac{(x^{2} -x)(x-1)}{(x-1)(x+4)}

\frac{(x-4)}{2}\times \frac{(x^{2} -x)}{(x+4)}
\frac{(x-4)}{2}\times \frac{x(x-1)}{(x+4)}

\frac{x(x-1)(x-4)}{2(x+4)}

OR

\frac{x(x^{2} -5x+4)}{2x+8}

OR
\frac{x^{3} -5x^{2} +4x}{2x+8}

Hence, the product of the given expression is \frac{x(x-1)(x-4)}{2(x+4)} OR \frac{x(x^{2} -5x+4)}{2x+8} OR \frac{x^{3} -5x^{2} +4x}{2x+8}

Learn more on Simplifying fractions here: brainly.com/question/27038950

Here is the complete and correct question:

What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x Over x squared + 3 x minus 4 EndFraction

#SPJ4

4 0
2 years ago
What is -4^2?<br><br> thanks!
Juliette [100K]
That 2 means we multiply 4 by itself 2 times, and -4 x -4 = positive 16.
~Deceptiøn
8 0
3 years ago
Read 2 more answers
If x^(3/5) = 1.84, then x^2 = ?<br> Show Work.<br> A.) 7.63<br> B.) 10.40<br> C.) 21.15
svetlana [45]
X^(3/5) = 1.84

x^(3/5) = (1.84)

Raise both sides of the equation to (5/3).  

This is so that on the side with x,  3/5 * 5/3 = 1.

(x^3/5 )^5/3 = (1.84)^(5/3)

x^(3/5  *  5/3) = 1.84^(5/3)

x^1 = 1.84^(5/3)
 
x = 1.84^(5/3)

But remember we are solving for x^2.

x = 1.84^(5/3)

x^2 = (1.84^(5/3))^2

x^2 =  1.84^(5/3  *2 )

x^2 =  1.84^(10/3)

Use a calculator here.

x^2 =  1.84^(10/3) ≈ 7.63

Option A.

Cheers!
5 0
3 years ago
What’s the surface area of the prism in square inches? A.300 B.360 C.390 D.460 helpppppp
butalik [34]

Answer:

2) 360 square inches

Step-by-step explanation:

First of all we have to verify that the base triangle is a right triangle

For this we use Pythagoras

h² = l1² + l2²

13² = 12² + 5²

169 = 144 + 25

169 = 169

Equality is fulfilled by what is a right triangle

Now we need to calculate the area of ​​the triangle

a = (12 in * 5 in) / 2

a = 60in² / 2

a = 30in²

 

Now we have to calculate the 3 areas of the rectangles

a1 = 10in * 13 in

a1 = 130in²

a2 = 10 in * 12 in

a2 = 120in²

a3 = 10 in * 5 in

a3 = 50in²

Now we must add all the calculated areas and the triangle 2 times

a1 + a2 + a3 + 2a =

130in² + 120in² + 50in² + 2 * 30in²

360in²

The surface area of the prism is 360in²

5 0
3 years ago
Read 2 more answers
Find two numbers such that the sum of their squares is 100. The square of the larger number is equal to the sum of the product o
Shtirlitz [24]

Answer with Step-by-step explanation:

Let x and y are two  numbers

According to question

x^2+y^2=100....(1)

Suppose x is larger than y

x^2=x(4y+8x)

x=4y+8x

x-8x=4y

-7x=4y

y=-\frac{7}{4}x

Substitute the value of y

x^2+(-\frac{7}{4}x)^2=100

x^2+\frac{49}{16}x^2=100

\frac{16x^2+49x^2}{16}=100

\frac{65}{16}x^2=100

x^2=\frac{16\times 100}{65}

x=\sqrt{\frac{1600}{65}}=\frac{40}{\sqrt{65}}=\frac{40}{65}\sqrt{65}=\frac{8}{13}\sqrt{65}

y=-\frac{7}{4}\times \frac{8}{13}\sqrt{65}=-\frac{14}{13}\sqrt{65}

3 0
3 years ago
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