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GREYUIT [131]
3 years ago
14

How are the triangles similar?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size. The triangles are congruent if, in addition to this, their corresponding sides are of equal length.

Step-by-step explanation:b

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How many solutions can be found for the set of linear equations? Y = 7(x + 2) and y = 7x + 14
Bogdan [553]

Answer:

infinite solution

Step-by-step explanation:

because  Y = 7(x + 2) and y = 7x + 14 are the same

y = 7(x+2) = 7x + 14

eliminate to see

y = 7x + 14

-(y = 7x +14)

= 0 = 0 + 0

so it is infinite solution

4 0
3 years ago
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To prove part of the triangle midsegment theorem using
bonufazy [111]

Answer:the length of GH is half the length of KL

Step-by-step explanation: Just took it on edg and was correct.

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X=-4 +6+ (11 +4(-3))
lapo4ka [179]

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

4 0
2 years ago
In a lab, a substance was heated by 6 °C each hour for 60 hours. What was the total change
Serggg [28]
The temp increased by 360 degrees since 6x60 is 360
5 0
2 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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