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Sonbull [250]
2 years ago
9

Write the following equation without using an absolute value sign. |y-x|, if y>x

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

y-x \leq 0 and y-x \geq 0

Step-by-step explanation:

As we know,

Absolute value of any given number is the positive number itself.  Therefore,

y-x \leq 0 and y-x \geq 0

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If a 20 ft tree casts a 15ft shadow, how long a shadow is cast​
Irina-Kira [14]

Answer:

25 ft

Step-by-step explanation:

c = √a^2 + b^2 = √20^2 + 15^2 = 25ft

Hooke me up with a 5 star and a thanks :)

4 0
2 years ago
the perimeter of this quarter circle with radius, r = 32mm. Give your answer as an expression in terms of π.
djverab [1.8K]

Answer:

16π + 64

Step-by-step explanation:

So the whole circumference is 64π

A quarter is 16π

Then you just have to account for the two radii.

16π + 64

3 0
3 years ago
Read 2 more answers
Help for a brainliest lol
Sergio [31]

Step-by-step explanation:

The answer is option b.

Explanation in the pic.

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6 0
3 years ago
Read 2 more answers
Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write
Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

  • Use double point formula and simplify it to get two eqaution.
  • Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

~ Keep all values.

(y  + 4) =  \frac{11 + 4}{2 + 1} (x + 1)

~ Simplify it.

y + 4 =  \frac{15}{3} (x + 1)

y + 4 = 5x + 5

5x - y + 1 = 0

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1}(x - x1)

~ Keep all values.

(y - 1) =  \frac{10 - 1}{4 - 1} (x - 1)

~ Simplify it.

y - 1 = 3 x - 3

3x - y - 2 = 0

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

m1 =  \frac{ - coeff. \: of \: x}{coeff \: of \: y}

m1 =  \frac{ - 5}{ - 1}

Therefore, m1 = 5

Slope of second equation.

m2 =  \frac{ - coeff \: .of \: x}{coeff \: .of \: y}

m2 =   \frac{ - 3}{ - 1}

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
R leaks out of a barrel so that the rate of change in the water level is proportional to the square root of the depth of the wat
Irina-Kira [14]
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
  y'(t) = k√(y(t)) . . . . for some proportionality constant k
  y(0) = 30
  y(1) = 29

We observe that a function of the form
  y(t) = a(t - b)²
will have a derivative that is proportional to y:
  y'(t) = 2a(t -b)

We can find the constants "a" and "b" from the given boundary conditions.
At t=0
  30 = a(0 -b)²
  a = 30/b²
At t=1
  29 = a(1 - b)² . . . . . . . . . substitute for t
  29 = 30(1 - b)²/b² . . . . . substitute for a
  29/30 = (1/b -1)² . . . . . . divide by 30
  1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
  b = 30 +√870 . . . . . . . . simplify

The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
5 0
3 years ago
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