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Goryan [66]
3 years ago
12

How can i solve that equation by factoring

Mathematics
2 answers:
Alina [70]3 years ago
6 0

Answer:

y =  {x}^{2}  + 8x + 15 \\ factors \:  =   3 \: and \:  5 \\ y =  {x}^{2}  + 3x + 5x + 15 \\ y = x(x + 3) + 5(x + 3) \\ y = (x + 5)(x + 3) \\ either \: (x + 5) = 0 \: or \: (x + 3) = 0 \\ x =  - 5 \: and \:  - 3

Hoochie [10]3 years ago
5 0

Answer:

y = ( x + 3 )( x + 5 )

Step-by-step explanation:

N/A

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3 years ago
5) Mrs. Bell went bowling again. Her bowling scores were 100, 172, 85, and 92. She wants
Alex73 [517]

Answer: She needs to bowl 120 or more on her next game.

Step-by-step explanation:

8 0
3 years ago
B=2.35 + 0.25x
Neko [114]

Answer:

D. 3.35

Step-by-step explanation:

First we need to form an equation and solve it to find the number of weeks when the prices were the same. Because the prices were the same we can say that b = c, and therefore form the equation:

2.35 + 0.25x = 1.75 + 0.4x - Now we nee to solve it and find x.

2.35 - 1.75 = 0.4x - 0.25x

0.6 = 0.15x

x = 0.6 ÷ 0.15

x = 4 weeks

So now we substitute x into the equation for beef and find the price.

b = 2.35 + (0.25 × 4)

b = 2.35 + 1

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7 0
3 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
The perimeter of this rectangle is 156 cm.
erastova [34]

Answer:

x = 15

Therefore, the length and width are 31 and 47.

Step-by-step explanation:

Perimeter = (2x + 1) + (2x + 1) + (3x + 2) + (3x + 2) = 156

Simplified,

10x + 6 = 156

Subtract 6 from both sides, then divide by 10.

10x = 150

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To find the length and width, substitute 15 (the value of x) into the individual equations.

2(15) + 1 = 31

3(15) + 2 = 47

5 0
3 years ago
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