Question

5. Given that 2x+329, the range of values of x is(1 Point)​

Answer 1

Answer:

The range of 2x+329:

$\mathrm{Range\:of\:}2x+329:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Step-by-step explanation:

Given the expression

$2x+329$

We know that range is termed as the set of values of the dependent variable for which a function is defined.

• We also know that the range of polynomials with odd degree is all the real numbers.

       i.e. $-\infty \:$

The given expression is a polynomial with an odd degree. Hence, the range of this expression will be all the real numbers.

Thus, the range of 2x+329:

$\mathrm{Range\:of\:}2x+329:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$