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melamori03 [73]
3 years ago
15

5^{2} \ + \ 4 ( 6 \ + \ 4 \ + \ 2^{2} )5 2 + 4(6 + 4 + 2 2 )

Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer std

Step-by-step explanation:

being a grimy bic

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I think if it takes me 8 hours then it will surely take him 8 hours

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The length of a regulation soccer field is 110 meters. The diagonal length of the same soccer field is about 133.14 meters. Abou
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Answer:

D

Step-by-step explanation:

Imagine this as a right angle triangle, where the diagonal length is the hypotenuse, the length is one side, and the width is the other.

We can therefore use Pythagoras' Theorem (or Pythagorean Theorem) to solve. The formula for this is a²+b²=c², where c is the hypotenuse, and a and b are the sides.

We can input the values we know to this formula to get the width. This gives 110²+b²=133.14² or 12100+b²=17 726.2596.

From there subtracting 12100 from both sides gives b²=5626.2596.

Square rooting b isolates it, leaving b=75.0083969.

Since the value of the diagonal was approximate, this can be assumed the b is 75m.

**This content involves Pythagoras' Theorem/Pythagorean Theorem, which you may wish to revise. I'm always happy to help!

8 0
3 years ago
2x-(10+4x)=3x-7 what is the answer
ZanzabumX [31]
X=-3/5

    3
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3 years ago
Solve by completing the square, please help​
Talja [164]

Answer:

 x = 4 + √ 38

Step-by-step explanation:

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3 years ago
Please help fast
Vladimir79 [104]

Answer:

  B:  II, IV, I, III

Step-by-step explanation:

We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below

  Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given

  Draw Line segment BE Draw Line segment FC — by Construction

  Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate

  Draw Line segment AG — by Construction

  Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate

  Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction

__

  II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem

  IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution

  I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)

  III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)

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  Line segment AD is a median Definition of a Median

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4 years ago
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