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natali 33 [55]
3 years ago
13

What is the vertex and the equation of the axis of symmetry of the graph of y=x2-6x-7?

Mathematics
2 answers:
seraphim [82]3 years ago
5 0

Answer:

The vertex is<u> (3,-16)</u>  and axis of symmetry is <u>3</u>

Step-by-step explanation:

The vertex of a quadratic equation f(x)=ax^{2}+bx+c is calculated as (\frac{-b}{2a},f(\frac{-b}{2a}))

and the axis of symmetry is  \frac{-b}{2a}

Compare equation y=x^{2}-6x-7 with f(x)=ax^{2}+bx+c

Where a= 1 and b = -6

so, x=\frac{-b}{2a}=\frac{-(-6)}{2}

      x=3

Now, put the value of x=3 in y=x^{2}-6x-7

y=(3)^{2}-6(3)-7

y=9-18-7

y=-16

Therefore, the vertex is<u> (3,-16)</u>  and axis of symmetry is <u>3</u>

Ray Of Light [21]3 years ago
3 0
X= -b over 2a = --6 over 2×1=3
y=3²-6(3)-7=-16
vertex is (3,-16)
axis of symmetry is 3
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