The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
<h3>What is the period of a cosine function?</h3>
The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
Read more on cosine function here: brainly.com/question/4599903
Answer:
34
Step-by-step explanation:
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The purchasing price of the store = $29.25.
They want to resale it at 54% markup of the purchasing price.
54% of 29.25 = 0.54 × 29.25.
On multiplying 0.54 and 29.25, we get 15.795.
Resale price = The purchasing price + Markup
= 29.25 + 15.795.
On adding 29.25 and 15.795, we get 45.045.
We can round it to 45 to the nearest dollar.
<h3>Therefore, the resale price to the nearest dollar is $45.</h3>
Answer:
Step-by-step explanation:
x is the number of students
(x+5) is the number of students and chaperons
$2.50·(x+5) is the amount of money the number of students and chaperons will pay for the trip, and that number should be less or equal than $90 because those are all the money they have
2.50(x+5) ≤ 90 which is the same as 90 ≥ 2.50(x+5)
The inequality "90 greater-than 2.50 (x + 5) "
90 > 2.50(x+5) is an error becase it excludes the possibility that <u>the trip can cost exact $90</u> so we need not just greater than > , yet greater and equal than ≥ sign
90 ≥ 2.50(x+5)
Answer:
Here is the way to get the answer
Step-by-step explanation:We use the formule: t=S/v. So:
+ t1= 160/100 = 8/5 hrs = 5760''
+ t2= 160/90 = 16/9 hrs = 6400''
=> t2-t1= 6400 - 5760 = 640'' = 10'40''
