Question

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 8/9 and P(T) = 1/10.

Answer 1

Answer:

$\textbf{ P(S \cap T) = \frac{89}{90} }$

Step-by-step explanation:

$\textup{Mutually events are events that cannot occur at the same time.}\\\textup{When you toss a coin you get only head or only tail but never both.}\\ \textup{In mathematical terms P(A) \cup P(B) = 0 , where A and B are mutually exclusive events. }\\\textup{We know the formula:}\\ P(A \cup B) = P(A) + P(B) - P(A \cup B) \\\textup{When A and B are mutually exclusive, it will simply be:}\\ P(A \cup B) = P(A) + P(B) \\\textup{Now given:}\\ P(S) = 8/9 , P(T) = 1/10$

$\implies P(S \cup T) = \frac{89}{10}$