Answer:
The answer is (5, 2)
Step-by-step explanation:
I. If move left = -x
move right = +x
So -2 - 3 = -5 => move left
-5 + 10 = 5 => move right
I suggest that move left and right is x cordinate
The answer is (5,2)
Is that correct?
(x)+(x+1)+(x+2)=228.
3x+3=228
3x=225
x=75
Integer 1: 75
Integer 2: 76
Integer 3: 77
75+76+77=228
Answer:
For a table for x and y values for this absolute value equation, it would look like this:
x --- y
3 --- (-5)
4 --- (-1)
5 --- 3
6 --- (-1)
7 --- (-5)
Step-by-step explanation:
When you are building a table for an absolute value graph, you start with the base formula for absolute value equations:
y = a|x-h| + k
In this equation (h, k) is the vertex and therefore the middle point. From there we go two numbers in each direction for our x values. And for every change in x, y changes by a factor of a.
If I did this correctly, the answer should be 2.72. Monday's stock price is given to you already, 30.80. To find Tuesday's, you'd add 1.20 to the already existing 30.80, that totals to 32. To find the number for Wednesday you would have to get the percentage and move the decimal so you can multiply it, it should end at .0625. You then get that number and multiply it by 32 because it was Tuesday's amount. From that you should get 2. You then subtract the 2 and the total for Wednesday is 30. You do the same for Thursday, you get the already existing number, 30, and multiply it by .04. That should end in 1.2. You then subtract that 1.2 and you should get 28.8 as your answer for Thursday. For Friday, the steps repeat. You take the 28.8 and multiply it by .025. That should equal to .72. You now subtract that .72 from Thursday's amount and should be left with 28.08 for Friday. Now that all the numbers are known, take the numbers for Monday and for Friday and then subtract them. (30.80-28.08) It should equal to 2.72.
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.



Now that we know the vertices of the surface

, we can parameterize it by

where

and

. The surface element is

With respect to our parameterization, we have

, so the surface integral is