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Vitek1552 [10]
1 year ago
8

Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +

4| − 5 < 7 x + 4 < 4 -3(x + 4) > 12 3(x + 4) < -12 x + 4 < 7 x + 4 > -4 x + 4 > -7
Mathematics
1 answer:
ziro4ka [17]1 year ago
6 0

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

x > -8

These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

#SPJ1

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Answer:

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How many roots does this has?<br>x^2+(2√5x)+2x=-10​<br>find Discriminant
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Given:

The equation is

x^2+(2\sqrt{5})+2x=-10

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Solution:

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x^2+(2\sqrt{5})x+2x=-10

The highest degree of given equation is 2. So, the number of roots is also 2.

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Since discriminant is 8\sqrt{5}-16\approx 1.89, which is greater than 0, therefore, the given equation has two distinct real roots.

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