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malfutka [58]
3 years ago
7

Emelia measures the weight of a rock to be 30 grams. The actual weight of the rock is 24 grams. Determine Emelia's percent error

.
Mathematics
1 answer:
Shalnov [3]3 years ago
6 0

Answer: 25%

Step-by-step explanation:

Given

Emelia measures the weight of the rock to be 30 gm

The actual weight was 24 gm

Percentage error is given by  

\Rightarrow \dfrac{\text{Deviation }}{\text{Actual value}}\times 100

Insert the values

\Rightarrow \dfrac{30-24}{24}\times 100\\\\\Rightarrow \dfrac{6}{24}\times 100\\\\\Rightarrow 25\%

Therefore, the percentage error is 25%.

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raj has 16 cups of flour he uses 3 1/2 cups to make bread and 4 3/4 cups to make muffins how many coups of flour does raj have l
DiKsa [7]

Answer:

31/4 cups of flour have left.

Step-by-step explanation:

3 1/2=7/2

4 3/4=19/4

--------------

16-7/2-19/4

64/4-14/4-19/4

31/4

6 0
3 years ago
Read 2 more answers
Rubber balls are packaged in a box with dimensions 8.5 cm, 5 cm, 5 cm.
Gre4nikov [31]

Answer:

42.9 cm^3

Step-by-step explanation:

Volume of the box= (base x width x height) = 8.5 x 5 x 5 = 212.5 cm^3

Radius of a ball = 1.5 cm

Volume of a ball = 4/3 * radius^3 * pi = 4/3 x 1.5^3 x pi = 14,137167 cm^3

Volume of the balls = 14,137167 x 12 = 169,646003 cm^3

Final answer = 212.5 - 169,646003 = 42.9 cm^3

7 0
3 years ago
A widget inspector inspects 12 widgets and finds that exactly 3 are defective.Unfortunately, the widgets then get all mixed up a
WITCHER [35]

Answer:

0.7455

Step-by-step explanation:

First, we note that there are CC_{12|3} = 220 ways of selecting the defective items.

The probability that the inspector will have to test at least 9 widgets would be 1 minus the probability that the inspector will have to test 8 or less widgets.

This is 1 - P(8 or less widgets have to be checked)

1 - \frac{C_{8|3} }{C_{12|3} }

= 1 - 56/220

= 1 - 0.2545

= 0.7455

8 0
3 years ago
Read 2 more answers
3+p/2=6 How do I solve this?
Diano4ka-milaya [45]

\boxed{\underline{\bf \: ANSWER}}

\sf\frac { 3 + p } { 2 } = 6 \\

Multiply both sides by 2.

\sf \: 3+p=6\times 2

Multiply 6 and 2 to get 12.

\sf \: 3+p=12

Subtract 3 from both sides.

\sf \: p=12-3

Subtract 3 from 12 to get 9.

\boxed{\bf \: p=9}

____

Hope it helps.

RainbowSalt2222

5 0
3 years ago
Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0
Sonja [21]

Answer:

\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}

Step-by-step explanation:

x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}

8 0
3 years ago
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