38.3 degrees celsius
Formula
(101°F − 32) × 5/9 = 38.333°C
Step-by-step explanation:
We have, Sorin hits a cricket ball straight up into the air. After 1.5 s, the ball is falling straight down with a speed of 6.5 m/s.
We want to find the initial vertical velocity of the ball.
The relation between initial speed, final speed, acceleration and time is given by using first equation of kinematics. Let v₀ is the initial speed. So,
Here, v = -6.5 m/s, t = 1.5 s and a = -g
So, the initial velocity of the ball is 8.2 m/s and the formula used is (1).
Answer:
therefore y= - (x-2)^2 + 5
Step-by-step explanation:
u do this by using this format here ..,
y=a(x-h)^2+k
sub in the vertex points as h=2 and k = 5 , since the 2 is positive its sign will be -2 in the brackets because when solving for x-2=0 it is x=2
y=a(x-2)^2+5
then with your (0,1) points plug that in as y and x
1=a(0-2)^2+5
1=a(-2)^2+5
1=4a+5
1-5=4a
-4=4a
a=-1
therefore y= - (x-2)^2 + 5
Answer:
angle 7 is 112
Step-by-step explanation:
angles 2 and 6 are congruent, and vertical angles are also congruent, so you know that angles 2 and 7 have the same value
Answer:
numerator is 1
denominator is 25
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