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kipiarov [429]
3 years ago
7

8(2 + x) = 3x + 16 + 5x

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>0</u></em></h2>

Step-by-step explanation:

8(2 + x) = 3x + 16 + 5x

=> 16 + 8x = 3x + 16 + 5x

=> 8x - 3x - 5x = 16 - 16

=> 0x = 0

=> <em><u>x = 0 (Ans)</u></em>

OverLord2011 [107]3 years ago
4 0

Answer:0

Step-by-step explanation:

everything cancels out

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She only paid $56 without tax
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Y is directly related to X, and Yis 81 when X is 27.<br> The constant of variation is
Arisa [49]

Answer:

3

Step-by-step explanation:

A direct variation is of the form

y = kx

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81 = k *27

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There are 4 fewer cats than dogs.<br>There are 2 cats. How many dogs<br>are there?​
allsm [11]

Answer:

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8 0
3 years ago
Read 2 more answers
What is a 40% decrease of 85?
Andrews [41]
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51 is your answer

6 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
2 years ago
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