If 9/10 tons of gravel got spread over 3 feet, then how much gravel is on each foot? Well, it's a ratio.
9/10 tons : 3 ft
So, we divide each side of the ratio by 3.
3/10 tons : 1 ft.
So, that 3/10 tons of gravel on each foot of road.
Writing the word problem as an equation you get:
x - 18 ≥ -12
Now to solve for x:
Add 18 to both sides of the inequality:
x ≥ -12 + 18
Simplify:
x ≥ 6
Answer:
Step-by-step explanation:
The straight line equation is:
y = m*x + b Where m is the slope of the line and b the intercept with y-axis, in our case y is the depth of the tank and x (time in lapsus of 3 hours).
The slope m = ( y₂ - y₁ ) / (x₂ - x₁)
We have point A ( 3 , 8 ) and point B ( 6 , 7 )
m = ( 6 - 3 ) / (7 - 8 ) m = -3
We see that each 3 hours time-depth decreases 1 in.
Then to find the depth at the beginning of x-axis
At noon 12 tank was 9 inches, three hours before at 9 in the morning the depth was 10 inches and:
9 in the morning 10
6 in the morning 11
3 in the midnight 12
12 in the night 13
Then 13 is the intercept with y-axis
then the equation is:
h = - 3*x + 13
Note x is time in lapsus of 3 hours
