All categories

3 years ago

If x equals 8 -(-2.25) and y equals 6-4.2-(-4.9) what is the value of x-y

Mathematics

1 answer:

slamgirl [31]3 years ago

8 0

Answer:

x = 10.25

y = 6.7

Step-by-step explanation:

X = 8 - (-2.25) = 10.25

Y = 6 - 4.2 - (-4.9) = 6.7

You might be interested in

Find the surface area of the figure. Round to the nearest tenth if possible.

Cloud [144]

Area of square base:
13 x 13 = 169
Area of triangular sides:
B x H/2
13 x 16/2 = 104
104 x 4 = because there are 4 triangular sides of the figure = 416
416 + 169 = 585in^2
590in^2

6 0

2 years ago

Two dice are rolled. What is the probability that the sum of numbers rolled is either 5 or 12?

Maksim231197 [3]

<u>ANSWER: </u>

The probability that sum of numbers rolled is either 5 or 12 is $\frac{5}{36}$

<u>SOLUTION: </u>

Given, Two dice are rolled.

We have to find what is the probability that the sum of numbers rolled is either 5 or 12

We know that, probability of an event = $\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Now, total outcomes for two dices = 6 for 1st dice x 6 for 2nd dice = 6 x 6 = 36.

Now, favourable outcomes = sum is 5 + sum is 12

= 4[(1,4), (2,3), (3, 2), (4, 1)] + 1[(6,6)]

= 5 total favourable outcomes.

Now, probability = 5/36

Hence, the probability that sum is either 5 or 12 is 5/36.

5 0

3 years ago

Find the x-intercept for 11x - 33y = 99

seropon [69]

It is 9. You have to add 33y, then divide by 11 and you get x = 3y + 9

7 0

3 years ago

Workout the size of angle x

Rashid [163]

Answer:

220

Step-by-step explanation:

220

4 0

3 years ago

Two friends sold many pieces of furniture and made $1550 during their garage sale. They had fifteen more $10 bills than $50 b

Novosadov [1.4K]

Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550 (1)

Also, since we have fifteen more $10 bills than $50 bills, n₁ = n₃ + 15 (2)

and we have 4 more than three times as many $20 bills as $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

3 0

3 years ago