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ZanzabumX [31]
2 years ago
8

What is the answer explain please

Mathematics
1 answer:
eduard2 years ago
6 0

Answer:

Pattern B

<h3> Explain:  </h3>

A quadratic relationship is characterized by constant second differences.

<em><u>Pattern A </u></em>

Sequence: 0, 2, 4, 6

First Differences: 2, 2, 2 . . . . constant indicates a 1st-degree (linear, arithmetic) sequence

__________________________________________________________

<em><u>Pattern B</u></em>

Sequence: 1, 2, 5, 10

First Differences: 1, 3, 5

Second Differences: 2, 2 . . . . constant indicates a 2nd-degree (quadratic) sequence

__________________________________________________________

<em><u>Pattern C</u></em>

Sequence: 1, 3, 9, 27

First Differences: 2, 6, 18

Second Differences: 4, 12 . . . . each set of differences has a common ratio, indicating an exponential (geometric) sequence

__________________________________________________________

Pattern B shows a geometric relationship between step number and dot count.

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BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

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3 years ago
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Answer:

Step-by-step explanation:

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dimaraw [331]
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where x = the percentage of games lost.  Cross multiply and divide to isolate the x:

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Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.
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you could also write

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if we cannot do a calculation directly (because there is a variable involved), we need to do and document the single steps for the individual parts involved.

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