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2 years ago

What is the answer explain please

Mathematics

1 answer:

eduard2 years ago

6 0

Answer:

Pattern B

<h3> Explain: </h3>

A quadratic relationship is characterized by constant second differences.

Pattern A 

Sequence: 0, 2, 4, 6

First Differences: 2, 2, 2 . . . . constant indicates a 1st-degree (linear, arithmetic) sequence

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Pattern B

Sequence: 1, 2, 5, 10

First Differences: 1, 3, 5

Second Differences: 2, 2 . . . . constant indicates a 2nd-degree (quadratic) sequence

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Pattern C

Sequence: 1, 3, 9, 27

First Differences: 2, 6, 18

Second Differences: 4, 12 . . . . each set of differences has a common ratio, indicating an exponential (geometric) sequence

__________________________________________________________

Pattern B shows a geometric relationship between step number and dot count.

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4 years ago

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Sphinxa [80]

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$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

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The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

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$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

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3 years ago

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