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Mashutka [201]
4 years ago
6

Write each phrase as an algebraic expression using the variable x

Mathematics
1 answer:
k0ka [10]4 years ago
6 0

Answer:

1. 2x + 4

2. 7x

3. x - 3

4. 15/x

5. 27 - x

6. 10/2x

7. x/8

8. 6 - x

9. x < 11

10. 2(8 + x)

Step-by-step explanation:

1.  "more" means addition and "twice a number" means multiplication

2. "product" means multiplication and "and" means addition

3. "less than" means subtraction

4. "divided" means division or /

5. "decreased" means subtraction

6. "divided" means division or / and twice a number means multiplication

7. "a number over" means "x divided by" or x/?"

8. "diminished" means subtraction

9. "less than" is the > symbol

10. "product" means multiplication and "the sum of" and "and" means addition


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Simplify (1-√3)(⅓+√3) leaving your answer in the form p+q√3​
Mars2501 [29]

Answer:

\frac{-8 +2\sqrt{3} }{3}

Step-by-step explanation:

When working with surds we need to take note of the roots present there.

To expand this equation we can do it the following way noting that √3 X √3 = 3

<em></em>

<em>Expanding (1-√3)(⅓+√3)</em>

1 X 1/3 = 1/3

1 X √3 = √3

-√3 X 1/3 =-√3/3

√3 X √3 = 3

hence, expanding the equation, we have

1/3 + √3 -√3/3 + 3

We can simply group the like terms and add them up.

[1/3 +3] +[√3-√3/3]

10/3 + \frac{2\sqrt{3} }{3}

= \frac{-8 +2\sqrt{3} }{3}

8 0
3 years ago
Twice the greater of two consecutive odd intergers is 13 less than three times the lesser. Find the intergers ​
erastova [34]

Answer:

\large\boxed{15, 16}

Step-by-step explanation:

2 consecutive integers represented as variables:

x, x + 1

Greater one: x + 1

Lesser one: x

Write as an equation

2(Greater) + 13 = 3(Lesser)

Substitute in known values

2(x + 1) + 13 = 3(x)

Multiply

2x + 2 + 13 = 3x

Subtract 2x from both sides of the equation

2 + 13 = x

Add 2 + 13 to simplify

x = 15

Lesser = x = 15

Greater = x + 1 = 15 + 1 = 16

\large\boxed{15, 16}

Hope this helps :)

3 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
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<h3>Answer: Choice C</h3>

Here's how the verification would look like

\frac{\sin^2x+\cos^2x}{\cos x} = \sec x

\frac{1}{\cos x} = \sec x using the identity here

\sec x =  \sec x

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The answer is $10

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