Step-by-step explanation:
x⁴+3x³-4x²=0
x²(x²+3x-4)=0
x²+3x-4=0
x²+4x-x-4=0
x(x+4)-1(x+4)=0
(x+4)(x-1)=0
x=-4 or 1
x can't be negative
therefore x=1
x+4=1+4=5
There are four questions related to this: how many number of
ways are there to award the prizes if:
a)
There are no restrictions? If k unalike awards
are there for n people and no person can get more than one
prize then there are: This leads to 100 × 99 × 98 × 97 = 94109400100 ×
99 × 98 × 97 = 94109400 ways in your case where n=100 k=4.
b)The person holding ticket 47 wins the grand
prize? After handing out the grand prize there are k=3 different rewards
left for n = 99 persons. Apply the same formula. Answer: 941094941094
c) The person holding ticket 47 wins one of the
prizes? 4 times case because there are 4 likelihoods when it
comes to the rewards that can be won by person 47. Answer: 37643763764376
d) The person holding ticket 47 does not win a prize? k=4 and n =99.
Person 4747 is left out. Answer: 9034502490345024
e) The person holding ticket 19 and 47 both wins prize? First gave out a
prize to 47. There are 4 possibilities. Then give out a prize
to 19. There are 3 likelihoods. Then the other prizes are gave
out: k=2 and n=98. Lastly you come to 4 × 3 × 98 × 97 =1140724
× 3 × 98 × 97 = 114072 possibilities.
we are given
three consecutive even integers
Let's assume
first even integer is x
second even integer is x+2
third even integer is x+4
sum of the first two consecutive even integers is equal to three times the third so, we can get equation as
now, we can solve for x
so, we get
first integer is -10
second integer is -10+2=-8
third integer is -10+4=-6.................Answer
Answer:
Graph B
Step-by-step explanation:
The <em>mass</em><em> </em>is independent, so it runs <em>horizontally</em>,<em> </em>and the <em>fuel</em> is dependent, so it runs <em>vertically</em>.
I am joyous to assist you anytime.
120+10+5=135
I don't know if all you're supposed to do is add or not... so i may be wrong....