Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:
The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days
Solving (b); The value of E when d = 30.
Substitute 30 for d in
<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
Step-by-step explanation:
The recursive rule is given by;
a = r .an-1 where n is the number of terms.
Given the sequence: -64, -16, -4 , -1, ....
This sequence is a geometric sequence with common ratio (r) = 1/4
Here, first term a1 = -64
Since,
\frac{-16}{-64} = \frac{1}{4}
\frac{-4}{-16} = \frac{1}{4} and so on....
The recursive rule for this sequence is;
an = 1/4*an-1
Answer:
The probability that Bentely will be selected first = 0.046
Step-by-step explanation:
The person will be randomly selected, it is not stated that sex is considered in the selection.
The total number of people present at the party = 10 + 12 = 22
The probability that Bentely will be selected first = 1/22
The probability that Bentely will be selected first = 0.046
2/3 = x/9
cross multiply and divide to find x. 9*2=18.......18/3=6. He would need 6 pints of red paint
