'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
The trick here is to notice that all 3 terms can be div. by 2:
2(x^2 + x - 12)
Note that -12 factors into -3 * 4 or -4 * 3. Thus,
x^2 + x - 12 = (x-4)(x+3), and so <span>2x2 + 2x − 24 = 2(x-4)(x+3).</span>
I think the answer is:
Rectangle: X X O X X
Rhombus: X X X X O
Square: X X X X X
I hope you got a good grade!!!
Answer:
0
Step-by-step explanation:
125×^6_81=0
×^6 we do not support this expression
ans = 0
Answer:
f(-3) = -12
g(-2) = -19
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 3x - 3
g(x) = 3x³ + 5
f(-3) is <em>x</em> = -3 for function f(x)
g(-2) is <em>x</em> = -2 for function g(x)
<u>Step 2: Evaluate</u>
f(-3)
- Substitute in <em>x</em> [Function f(x)]: f(-3) = 3(-3) - 3
- Multiply: f(-3) = -9 - 3
- Subtract: f(-3) = -12
g(-2)
- Substitute in <em>x</em> [Function g(x)]: g(-2) = 3(-2)³ + 5
- Exponents: g(-2) = 3(-8) + 5
- Multiply: g(-2) = -24 + 5
- Add: g(-2) = -19
