What is equivalent to (x – 8)(x

Paul purchased 3 video games for $17.25 each. Which expression is the best choice to help him determine the total amount of mone

mr_godi [17]

Answer:

The answer is C or (3) × (17.25) = 51.75; He spent $51.75.

Step-by-step explanation:

i say this because 17.25 time 3 equal 51.75

6 0

2 years ago

HELP PLEASE!!!!! IT DOESN'T EVEN SHOW UP ON GOOGLE!!!!!!!!!!!!!1

meriva

0.032 is the interest
since it is half a year, double this one
0.032 x 2 = 0.064

your formula is A = P(1 + (r/n)^nt
P is principle
R is rate
N is number of times
T is time

A = <span>32,675.12(1 + (0.032/2)^2(5)
A = 32675.12(1 + (0.016)^10
A = 32675.12(1.016)^10
A = 32675.12 (1.172)
A = 38295.24064
Your answer is ~38295.24

hope this helps

none of the answers make sense, because you can withdraw a lot more money from your bank account than that, unless you are missing some numbers and stuff</span>

5 0

2 years ago

Read 2 more answers

Will give brainliest!

fiasKO [112]

Let's give some distances
100 up 100 flat 100 down meters
then return 100 up 100 flat 100 down

time required (distance/rate = time ) 200/100 + 200/120 + 200 / 150 = 5 hr

distance 600

distance / time = average speed = 600/5 = 120 m/s

5 0

2 years ago

A random sample of 100 people was taken. Eighty-five of the people in the sample favored Candidate A. We are interested in deter

lbvjy [14]

Answer:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.85$ estimated proportion of people who favored candidate A

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.8.:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

8 0

2 years ago

A country has a total biocapacity of 6.21 ha/person, a biocapacity of grazing land of 0.85 ha/person, and a biocapacity of fores

leonid [27]

Answer:

44.8 %

Step-by-step explanation:

Let p = the number of people. Then

Total biocapacity = 6.21p ha

Grazing biocapacity = 0.85p ha

Forest biocapacity = <u>2.53p </u>

Grazing + forest = 2.78p ha

$\text{Percent grazing + forest} = \dfrac{\text{grazing + forest}}{\text{Total}} \times 100 \, \% \\\\= \dfrac{\text{2.78p ha}}{\text{6.21p ha}} \times 100 \, \% = \mathbf{44.8 \,\%}$

6 0

2 years ago

What is equivalent to (x – 8)(x – 6)?