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4 years ago

Whats 123/234/332-34+6.893.00+12-45/123

Mathematics

1 answer:

vlada-n [284]4 years ago

6 0

Answer:

=15

Step-by-step explanation:

well if your smart enough you'll know its 15

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These two lines are<br> Graphs of non-proportional relationship makes makes them nonproportional

Tpy6a [65]

9514 1404 393

Answer:

C They do not go through the origin

Step-by-step explanation:

The graph of a proportional relationship is a straight line with a y-intercept of 0. These lines do not go through the origin, so do not describe a proportional relationship.

5 0

3 years ago

Solve the equation for x: 5/6x + 10 =30

Anna11 [10]

Solve the rational equation by combining expressions and isolating the variable

Exact Form:

Decimal Form:

0.041

3 0

3 years ago

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Use the Distributive Property to rewrite each expression.<br><br> 4 (h - 5g)

snow_tiger [21]

Answer:

4h - 20g

Step-by-step explanation:

According to the Distributive Property, you should multiply (distribute) the 4 across the parentheses.

4(h - 5g)

= (4•h) - (4•5g)

= 4h - 20g

5 0

3 years ago

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PLEASE HELP ILL GIVE BRAINLY!!!!!!

sergey [27]

It would be -4 cuz when x = -3, y=-4

3 0

3 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

3 years ago