Answer:
what do you have to do this?
Step-by-step explanation:
what grade and type of math is this?
2x+2y=38
y=x+3
First you would substitute the y for x+3
2x+2(x+3)=38
You would multiply the 2 by the x+3
2x+2x+6=38
Add the 2x and the 2x
4x+6=38
Subtract the 6 on both sides
4x=32
Divide the 4 on both sides
x=8
Now substitute the x in the second problum for 8
y=8+3
Add the 8 and the 3 to solve for y
y=11
Your answers
x=8
y=11
the correct answer would be A:(8,11)
72 ÷ o should be the algebraic expression.
If your solving for B then its B<43/3
