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2 years ago

Use the Distributive Property to rewrite each expression. 4 (h - 5g)

Mathematics

2 answers:

snow_tiger [21]2 years ago

5 0

Answer:

4h - 20g

Step-by-step explanation:

According to the Distributive Property, you should multiply (distribute) the 4 across the parentheses.

4(h - 5g)

= (4•h) - (4•5g)

= 4h - 20g

Luden [163]2 years ago

5 0

4h - 20h, multiply the 4 by each term.

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Two equivalent equations of the line in point slope form for (-4,8) and (0,5)

34kurt

Answer:

Equation of line 1 is 3 X - 4 Y = 20

Equation of line 2 is 3 X + 4 Y = 20

Step-by-step explanation:

Given co ordinates of points as,

( -4 , 8) and (0 , 5)

From the given two points we can determine the slop of a line

I. e slop (m) = $\frac{(y2 - y1)}{(x2 - x1)}$

Or, m = $\frac{(5 - 8)}{(0 + 4)}$

So, m = $\frac{(-3)}{(4)}$

Now equations of line can be written as ,

Y - y1 = m ( X - x1)

At points ( -4 , 8)

Y - 8 = $\frac{(-3)}{(4)}$ (X + 4)

So , Equation of line 1 is 3 X - 4 Y = 20

Again with points ( 0 , 5)

Y - 5 = $\frac{(-3)}{(4)}$ ( X - 0)

So, Equation of line 2 is 3 X + 4 Y = 20

Hence Equation of line 1 is 3 X - 4 Y = 20 and Equation of line 2 is 3 X + 4 Y = 20 Answer

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3 years ago

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3 years ago

Draw a model of square root of 12 using perfect squares

Shkiper50 [21]

Answer:

The answer is " $\sqrt{12}$ is not a perfect square".

Step-by-step explanation:

12 is not a perfect square because it is the natural number, and no other natural number would square the number 12, that's why it is not a perfect square.

If we calculate the square root of $\sqrt{12}$ . so, it is will give $2\sqrt{3}$ that is not a perfect square root which can be described as follows:

$\Rightarrow \sqrt{12}= \sqrt{2\times 2\times 3}$

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$\bold{\sqrt{12}}$ is not a perfect square root.

7 0

3 years ago

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A sandbag is released from a hot air balloon that is 400ft above the ground. Using the falling object model, h = –16t2 + s, wher

Aleonysh [2.5K]

Answer:

It takes 5 seconds for the sandbag to hit the ground

Explanation:

Given:

Height at which the sand bag is released from the hot air balloon $= -400 f t$

To find:

Time taken for the sandbag to hit the ground, t =?

Solution:

The initial height =s

Initially the height will be 0

Hence $s=0$

the falling object model equation

$h=-16 t^{2}+s$

Substituting the values we get,

$h=-16 t^{2}+s$

$400=16 t^{2}$

$t^{2}=\frac{400}{16}$

$t^{2}=25$

$t=\sqrt{25}$

$t=5 \text { seconds }$

Result:

Thus it takes 5 seconds for the sandbag to hit the ground

3 0

3 years ago