Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.
And the expressions for each arc in the diagram also given as:
Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.
Hence, we will get the system of equations as following:
Arc QR = Arc LN
2x - y = 11 ...(1)
Arc OP = Arc VW
5x + y = 10 ...(2)
We need to find the value of x. So, we can add the equations to eliminate y so that we can solve the equations for x. Therefore,
2x+5x = 11 + 10
7x = 21
Divide each sides by 7.
So, x= 3
Answer: A
Step-by-step explanation:
Yes it is the same. 1/4 +1/4 = 1/2. so 9/10-1/2=9/10-1/2
How many minutes did it take him to cover 1 mile? 5 minutes.
Answer: 1080 ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Determine the values of b1, b2, and b3, the sides of the triangular base. Also determine the value of h, the height of the triangular base and l, the length of the prism (the length between the bases).
The sides of the triangular base are:
b1 = 13 in.
b2 = 14 in.
b3 = 15 in.
The triangular base is a right triangle, and so the height is one of our sides. We will use
h = 12 in.
The length of the prism is
l = 20 in.
total surface area = bh + (b1+b2+b3)*l
bh = 12*20 = 240 ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
l * (b1+b2+b3) = 20*(13 + 14+ 15) = 840 ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
TSA = bh + l * (b1 + b2 + b3) = 240 + 840 = 1080 ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
to know more about prism,
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