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3 years ago

(6ab+a-4)-(ab-1) please help me!

2 answers:

8 0

$(6ab + a - 4)-(ab-1) \\ \\ 6ab + a - 4 - ab + 1 \\ \\ (6ab - ab) + a - 4 + 1 \\ \\ 5ab + a - 4 + 1 \\ \\ 5ab + a - 3 \\ \\ Answer: \fbox {5ab + a - 3}$

Illusion [34]3 years ago

4 0

☆Let's simplify step-by-step!☆
☆Question you asked:
6ab+a−4−(ab−1)

☆Distribute the Negative Sign:
6ab+a−4+−1(ab−1)
6ab+a+−4+−1ab+(−1)(−1)
6ab+a+−4+−ab+1

☆Combine Like Terms:
6ab+a+−4+−ab+1
(6ab+−ab)+(a)+(−4+1)

☆Answer:
5ab+a+−3

☆I hope this helps!☆

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romanna [79]

Answer:

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3 years ago

A surf instructor has an initial fee of $12 and charges $8 per hour for lessons.

OverLord2011 [107]

I think it is y = 8x + 12

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3 years ago

Read 2 more answers

A player chooses one of the numbers 1 through 4. After the choice has been made, two regular four-sided (tetrahedral) dice are r

d1i1m1o1n [39]

Answer: $=\frac{-1}{16}$

Step-by-step explanation:

given data:

number to be chosen from = 1,2,3,4.

Solution:

ways the number can show

$2*3*1=6$ ways for your number to appear once.

$1*1=1$ ways for your number to appear twice.

$3*3=9$ ways for your number not to appear at all

$= \frac{6(1) + 1(2) - 9(1)}{16}$

$= \frac{6+2-9}{16}$

$=\frac{-1}{16}$

expected return of the player is $=\frac{-1}{16}$

4 0

3 years ago

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard

avanturin [10]

Answer:

There is a 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean \mu and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard deviation of 2503 miles.

This means that $\mu = 33208, \sigma = 2503$ .

What is the probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct?

This is the pvalue of Z when $X = 33208+633 = 33841$ subtracted by the pvalue of Z when $X = 33208 - 633 = 32575$

By the Central Limit Theorem, we have t find the standard deviation of the sample, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{2503}{\sqrt{49}} = 357.57$

X = 33841

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{33841 - 33208}{357.57}$

$Z = 1.77$

$Z = 1.77$ has a pvalue of 0.9616

X = 32575

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{32575- 33208}{357.57}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 0.9616 - 0.0384 = 0.9232 = 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

4 0

3 years ago

Help pls :))))))))))))

Aneli [31]

Answer:

yes, the triangle are congruent by SAS

6 0

2 years ago