Complete the equation of the line through ( 4 , -8 ) and ( 8 , 5 )

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( 4 ,-8)

point B( x₂ , y₂) ≡ (8 , 5)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(-8))=(\frac{5-(8)}{8-4})\times (x-4)\\ \\(y+8)=\frac{13}{4}(x-4)\\\\4(y+8)=13(x-4)\\4y+32=13x-52\\13x-4y=84...............\textrm{which is the required equation of the line AB}$

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

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When the shaded region below is rotated about the x-axis the resulting solid is a circular cone with radius 2 m and height 3 m.

WARRIOR [948]

Answer:

Therefore, the volume of the cone is V=4π.

Step-by-step explanation:

From task we have a circular cone with radius 2 m and height 3 m. We use the disk method to find the volume of this cone.

We have the formula:

$\boxed{V=\int_0^h\pi \cdot \left(\frac{r}{h}x\right)^2\, dx}$

We know that r=2 and h=3, and we get:

$V=\int_0^3\pi \cdot \left(\frac{2}{3}x\right)^2\, dx\\\\V=\int_0^3 \pi \frac{4}{9}x^2\, dx\\\\V= \frac{4\pi}{9} \int_0^3 x^2\, dx\\\\V= \frac{4\pi}{9} \left[\frac{x^3}{3}\right]_0^3\, dx\\\\V= \frac{4\pi}{9}\cdot 9\\\\V=4\pi$