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Citrus2011 [14]

2 years ago

8

Hoang has worked as a nurse at Springfield General Hospital for 7 years longer than her friend Bill. Two years ago, she had been

1 answer:

Evgesh-ka [11]2 years ago

3 0

Answer:

$Bill\to 9\ years$

$H \to 16\ years$

Step-by-step explanation:

Let

$H \to Hoang$

$B \to Bill$

Currently:

$H = B + 7$

Two years ago

$H - 2 = 2 * (B -2)$

Required

H and B

We have:

$H - 2 = 2 * (B -2)$

Open bracket

$H -2 =2B - 4$

Add 2 to both sides

$H -2+2 =2B - 4+2$

$H =2B -2$

Substitute $H = B + 7$

$B + 7 =2B -2$

Collect like terms

$2B - B =7+2$

$B = 9$

Substitute $B = 9$ in $H = B + 7$

$H = B + 7$

$H = 9 + 7$

$H = 16$

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A scientist measured the width of a square flake of gold to be7.3 x 10 -4mm what is the area of the flake

irakobra [83]

The area of square flake of gold is $53.29 \times 10^{-8} \mathrm{mm}$

<h3><u>Solution:</u></h3>

Given that width of square flake of gold is $7.3 \times 10^{-4}$ millimeter

To find : Area of square flake

Since gold flake is in shape of square, we can use area of square formula

<em><u>The formula for area of square is given as:</u></em>

$area = s^2$

where "s" is the length of one side

$\begin{array}{l}{\text { Area of a square flake }=\left(7.3 \times 10^{-4}\right) \times\left(7.3 \times 10^{-4}\right)} \\\\ {\text { Area of a square flake }=53.29 \times 10^{8}}\end{array}$

Hence , the calculated area of flake is $53.29 \times 10^{-8} \mathrm{mm}$

7 0

2 years ago

A 6 sided die numbered 1 to 6 is rolled . Find the probability that in the roll of the results is an odd number or less than 4

stellarik [79]

Answer:

4/6 or 66%

Step-by-step explanation:

Odd numbers from 1 to 6 are: 1, 3, 5

Numbers less than 4 are: 1, 2, 3

So there are 4/ 6 possible outcomes.

So the probability is 4/6 or 66%.

3 0

2 years ago

Help me asap!!!thanks

Elza [17]

Answer: 55cm^2

Step-by-step explanation:Area of a parallelogram= bh, so the base and height for this new one are base of 11 and height 5. so 11*5=55

3 0

3 years ago

find a set of parametric equations of the line the line pases through the point (2,3,4) and is parallel to the xz-plane and the

joja [24]

Answer:

$x=2, y=3, z=4+t$

Step-by-step explanation:

For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

$u= (u_x, u_y, u_z)= (0,0,1)$

Or any factor of u but for simplicity let's take the unitary vector.

Then the parametric equations are given by:

$x= P_x + u_x t$

$y= P_y + u_y t$

$z= P_z + u_z t$

Where the point given $P=(2,3,4)= (P_x , P_y, P_z)$

And then since we have everything we can replace like this:

$x= P_x + u_x t 2+ 0*t = 2$

$y= P_y + u_y t= 3+ 0*t = 3$

$z= P_z + u_z t = 4+ 1t = 4+t$

$x=2, y=3, z=4+t$

6 0

2 years ago

I have no idea how to solve this

Anvisha [2.4K]

Answer:

awww neither do i

Step-by-step explanation:

lol I got a 72 on my matb homework going to go jump off a cliff

3 0

2 years ago