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Masteriza [31]
2 years ago
6

Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2). It's dilated by a factor of 2 with the center of dila

tion at the origin. What are the coordinates of the resulting quadrilateral A'B'C'D'?
Mathematics
1 answer:
Alexeev081 [22]2 years ago
8 0

Given:

Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2).

It's dilated by a factor of 2 with the center of dilation at the origin.

To find:

The coordinates of the resulting quadrilateral A'B'C'D'.

Solution:

The figure dilated by a factor of 2 with the center of dilation at the origin. So, the rule of dilation is

(x,y)\to (2x,2y)

Using the above rule, we get

A(-1,-2)\to A'(2(-1),2(-2))=A'(-2,-4)

B(-1,3)\to B'(2(-1),2(3))=B'(-2,6)

C(4,3)\to C'(2(4),2(3))=C'(8,6)

D(4,-2)\to D'(2(4),2(-2))=D'(8,-4)

Therefore, the coordinates of the resulting quadrilateral A'B'C'D' are A'(-2,-4), B'(-2,6), C'(8,6) and D'(8,-4).

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