Question

A man flies a kite with a 100 foot string the angle of elevation of the string is 52 how high off the ground is the kite

Answer 1

Answer:

          About  78.8 ft

Step-by-step explanation:

$\sin52^o=\dfrac H{100}\\\\H=100\sin52^o\\\\H\approx78.8\ ft$

Answer 2

The kite is approximately 78.80 feet off of the ground.


Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
=
o
p
p
h
y
p

sin
52
o
=
h
100
f
t

100
sin
52
o
=
h

100
(
0.7880
)
=
h

78.80
f
t
=
h