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LekaFEV [45]
2 years ago
12

61. Often it is necessary to rearrange an equation so that one variable is expressed in terms of others. For example, the equati

on D = 3t expresses D in terms of t. To express t in terms of D, divide both sides of this equation by 3 to obtain D/3 = t.
(a) Solve the equation C = 2πr for r in terms of C.
(b) Solve the equation p = 2w + 2h for w in terms of p and h.
(c) Solve the equation 3x − 2y = 6 for y in terms of x.
Search entries or author
Mathematics
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

after it is necessary to rearrange and equations for that one variable is expressed in terms de in term of tea to express it in terms of d we need to solve the equation c is equal to fir for our in terms of c solve the equation p is equal to 2 w plus two hours for w in terms of p and h

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X=1/16y^2 the directrix of the parabola is
yan [13]
To solve this problem you must apply the proccedure shown below:

 1. You have the following equation of a parabola, given in the problem above:

 x<span>=1/16y^2

 2. Then, based on the graph attached, you have:

 p=y^2/4x
 p=8^2/(4)(4)
 p=64/16
 p=4

 3. The directrix is:

 directrix=h-p
 directrix=0-4
 directrix=-4

 The answer is:-4</span>

3 0
3 years ago
What is this answer?
Rainbow [258]

Answer:

None of the above

Step-by-step explanation:

3^3=81

-3^3=-81

6^3=216

-6^3=-216

5^3=125

7 0
3 years ago
Read 2 more answers
This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.
Ugo [173]

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

A_{rectangle}=10\cdot 6=\underline{60} \\A_{halfcircle}=\frac{3.14\cdot3^2}{2}=\underline{14.13} \\A_{total}=A_{rectangle}+A_{halfcircle} =60+14.13=\boxed{74.13\approx74}

The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

3 0
3 years ago
Read 2 more answers
What is the value of x in the equation below?<br> 12 – 2(x-1)=6
JulijaS [17]
X=25 in this equation. But if u divide by 12 it’s -25
5 0
3 years ago
Read 2 more answers
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
Read 2 more answers
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