Answer:
True.
Step-by-step explanation:
Let a,b,c integers and a | (ab+c), that is to say that there exist a integer k such that ab+c = ka. Then:
ab+c = ka
c = ka-ab
c = a(k-b). So, c is a multiple of a, that is a | c.
Working on x and y first, we get:
<span><span><span>x6 / </span><span>x3</span></span>= <span>x3</span></span> and
<span><span><span>y6/ </span><span>y12 </span></span>= 1/ <span>y6</span></span> so, we have:<span><span> 2 <span>x3 / </span></span><span>y6
Entering values in original equation, we get:
</span></span><span>(2 <span>x3/ </span><span>y6</span><span>)^2</span></span>=4 x^6 / y^12
It is better to illustrate the problem. As you can see on the figure, angle A and angle C are opposite angles. First, we define parallelogram. Parallelogram is a quadrilateral with two sets of parallel sides. Moreover, the opposite sides and the opposite angles are equal.
From the definition alone, there is no need to solve. Angle C = Angle A =
55 °.