The equation of line q is y = –4 x + 57. Perpendicular to line q is liner , which passes through the point(–10, –7) .What is the

Question

OleMash [197]

3 years ago

12

The equation of line q is y = –4 x + 57. Perpendicular to line q is liner , which passes through the point(–10, –7) .What is the

equation of line r ?

Mathematics

1 answer:

NeX [460] · Answer 1 · 2022-06-06T22:30:26+03:00

Answer:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

Step-by-step explanation: