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OleMash [197]
3 years ago
12

The equation of line q is y = –4 x + 57. Perpendicular to line q is liner , which passes through the point(–10, –7) .What is the

equation of line r ?
Mathematics
1 answer:
NeX [460]3 years ago
6 0

Answer:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

Step-by-step explanation:

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natulia [17]

Answer:

4/5

Step-by-step explanation:

SImply use slope formula. We see the graph has defined points at (5, 4), and (-5, -4).

m=(Y2-Y1)/(X2-X1)

(4-(-4))/(5-(-5))=8/10

Simplify 8/10

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4 0
2 years ago
What is the electric field strength at a distance of 15 cm from a point charge that has 12
ivann1987 [24]
The formula is E= kQ/ d^2

k is 9x10^9
i changed 15 cm to 0.15 m

=> 9x10^9 x 12 OVER (0.15)^2

the answer is 4.8x10^12 N/C

but this is the electric field.

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8 0
3 years ago
The height in meters of a rocket launched from the ground after t seconds is modeled by h(t)=-9.8r^2+49t. Graph a graph represen
Darina [25.2K]
9.8t^2-49t+40=0

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1.027<t<3.97
7 0
4 years ago
Read 2 more answers
3[(8-2)-5]+7 í need help on this answer
Anna11 [10]

Answer:

10

Step-by-step explanation:

3[(8-2)-5]+7

3[6-5]+7

3[1]+7

3+7

10

6 0
4 years ago
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Yuri [45]
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