Find 3 consecutive odd integers whose sum is 225, explain please

2 answers:

4 0

73,75,77

do it like this
(x-2)+x+(x+2)=225
add it all up
3x=225
x=75

so, 75-2=73
and 75+2=77 so, 73,75,77 is the answer

Gre4nikov [31]3 years ago

3 0

Three consecutive integers whose sum is 225 are 74, 75, and 76.

Three consecutive odd integers add up to 225. This means the middle of the three numbers is one third of 225.

225/3=75

The middle number is 75. The other two numbers are 74 and 76.

Three consecutive integers whose sum is 225 are 74, 75, and 76.

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7 times as much as sum of 1/3 and 4/5

Salsk061 [2.6K]

So the formula is
7*(1/3+1/5) = x

First find the common denominator of the fractions. In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths. To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.

So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it

5 * 1 = 5 so 1/3 converts to 5/15

Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it

3*4 = 12 so 4/5 converts to 12/15

Now we add 5/15 and 12/15 = 17/15 so we have our formula now to

7*17/15

We make seven a fraction 7/1 and multiply across 7*17 = 119 and 15 * 1 = 15

We have 119/15 which when we divide and get 7 14/15 as your answer

8 0

3 years ago

Read 2 more answers

Let g (2) = 22 – 5 and h (2) = 22 +1. Find (g+h) (2)

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Answer:

23 + 17 = 40 :)

8 0

2 years ago

What is another strategy that you can use to multiply 2 digit by 2 digit numbers?

ipn [44]

You may write them separating the units and tens digits, and then use FOIL to add 4 easy tems. For example, let's compute $21\cdot 36$ :