What is the approximate perimeter of △DEF?
1 answer:
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Answer:
The required answer is .
Step-by-step explanation:
Consider the provided numbers:
We need to subtract in base 4.
The place value of 201 is:
1 is at units place, 0 is at four's place and 2 is at 4 squared place.
The place value of 32 is:
2 is at units place and 3 is at four's place.
201
- 32
Start subtracting the numbers from the unit place.
Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.
Also change 0 to 4 because we have borrow 4 from squared place.
Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.
Now the number will look like this:
135
- 32
Now subtract the number as shown.
135
<u>- 32</u>
103
Hence, the required answer is .