Answer:
0.0778 = 7.78% of the population are considered to be potential leaders
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 580 and a standard deviation of 120.
This means that
What proportion of the population are considered to be potential leaders?
Proportion of those who exceed 750, that is, 1 subtracted by the vpalue of Z when X = 750.
has a pvalue of 0.9222
1 - 0.9222 = 0.0778
0.0778 = 7.78% of the population are considered to be potential leaders
Answer:
7 , 11
Step-by-step explanation:
Let the second number be 'x'
the first number = x - 4
Twice the second number : 2*x = 2x
5times first = 5*(x -4) = 5*x - 5*4 = 5x - 20
13 less than 5 times the first = 5x - 20 - 13 = 5x - 33
5x - 33 = 2x
Add 33 to both sides
5x - 33 + 33 = 2x +33
5x = 2x + 33
Subtract '2x'from both sides
5x - 2x = 2x - 2x + 33
3x = 33
Divide both sides by 3
x = 11
First number = x - 4 = 11 - 4 = 7
The numbers are 7 , 11
Answer: See explanation
Step-by-step explanation:
You didn't give the options but let.me solve the number of left handed girls and you then choose the closest answer to the value that I get.
Surprising survey revealed that 32% of the 475 girls at mason Junior high school were left handed. Therefore, the number of left handed girls will be:
= 32% × 475
= 32/100 × 475
= 0.32 × 475
= 152 left handed girls
-2n-2=12
add 2 to both sides
-2n=14
divide -2 to both sides
n=-7