Carbon Monoxide would have been mostly to effect the embryo as it targets the respiration system.
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Carbon is released into the atmosphere
NUCLEAR FUSION, hope it helps
Answer:
a. True, b. False, c.True, d. True
Explanation:
a. Base excision repair is started by a DNA glycosylase that recognizes the changes and removes the altered base by cleavage of the glycosidic bond binding the base and the deoxyribose sugar together.
b. Nucleotide excision repair works by a cut-and patch mechanism that removes their heavy lesions, including pyrimidine dimers and nucleotides . Endonucleases are responsible for the lesion of the damaged strand.
c. Nucleotide excision repair is initiated by the proteins namely UvrA, UvrC, and UvrB in Escherichia coli.
-UvrD (helicase II) later removes the damaged strand
-DNA polymerase I (PolI) fills in the resulting gap.
d. DNA glycolases removes the damaged nitrogenous base.
-It leaves the sugar-phosphate backbone intact and thus creating an apurinic/apyrimidinic site, which is commonly referred to as an AP site.
e. Xeroderma pigmentosum complementation group A(XPA)
-This is an essential protein in the nucleotide excision repair pathway.
- It helps to make a pre-incision complex along with other proteins.
Answer:
Cell population growth can be represented by the number <u><em>2</em></u> with an exponent, where the exponent increases by <u><em> 1</em></u> in each generation.
Explanation:
As we know, every cell doubles after the process of cell division. Hence the cell population growth is represented by the number 2. The cell population growth is also known as the doubling time of a cell. The proliferation of cells is often written as:
Nt = N0 2tf
Where,
Nt is the number of cells at a particular time t.
N0 is the initial number of cells.
f is the frequency of cell cycles
