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Igoryamba
3 years ago
9

This is the second stage of cellular respiration and takes place in the mitochondrial matrix. During this stage the decompositio

n of pyruvate to carbon dioxide is completed
Biology
2 answers:
RoseWind [281]3 years ago
8 0
The kerb cycle is the second stage and the last stage is the electron transport chain
Mashutka [201]3 years ago
8 0

Answer:

Krebs cycle

Explanation:

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Readme [11.4K]

Answer:

maybe

Explanation: both idk for sure sry i tried

3 0
3 years ago
How do leaves help with cellular reputation ?
charle [14.2K]
Photosynthesis is the process by which plants use light energy to convert carbon dioxide and water into sugars...Respiration occurs when glucose combines with oxygen to produce useable cellular energy. This energy is used to fuel growth and all of the normal functions.
6 0
4 years ago
How many atp equivalents are consumed in the conversion of each of the following to a glucosyl residue in glycogen?
Nina [5.8K]
<h3><u>Answer;</u></h3>

Dihydroxyacetone phosphate - 1

Fructose-1,6-bisphosphate - 1

Pyruvate - 13

G-6-P - 1

<h3><u>Explanation;</u></h3>

1) Dihydroxyacetone phosphate = 1

G1P + GTP --> UDPG + PPi two P is equivalent to 2 ATP --->2 ADP + Pi) Therefore, two ATP equivalents - but UDP is the product and only one P needed

2 DHAP --> F1,6-BP -->F6P --> G6P -->G1P -->UDPG --> glucosyl residue

2) Fructose 1,6-bisphosphate = 1

3) Pyruvate = 13

2 pyr + 2 ATP --> 2 OAA

2 OAA + 2 GTP --> 2 PEP

2 PEP --> 2 2PG --> 2 3PG

2 3PG + 2 ATP --> 2 1,3 BPG

2 1,3 BPG + 2 NADH --> 2 G3P

2 NADH = 6 ATP

2 G3P --> DHP + G3P --> FDP -- > F6P + P

F6P --> G6P --> G1P

G1P + UTP --> UDPG + PP

4) Glucose-6-phosphate = 1

G6P -->G1P G1P + UTP --> UDP-GLC + 2 Pi

UDP-Glc + glycogen --> glycogen+ 1 Glc

4 0
3 years ago
If the conservative model had been correct, how many generations of bacterial cell division would have had to pass before mesels
Reil [10]

No generations or hybrid would form before meselson and stahl would have observed evidence of a band in the cscl gradient.

The conservative model predicts that, following a single replication, half of the newly formed DNA double helices will be made entirely of the original, or old, DNA, and the other half will be entirely new. Then, each double helix would be completely replicated during the second round of replication. After that, 25% of the double helices would be all new, and 25% would be entirely old. Thus, the fraction of entirely new DNA double helices would increase with each succeeding round of replication, but the total number of completely unique DNA double helices would remain constant. Therefore, no hybrid DNA molecule containing 14N and 15N is replicated in the conservative model.

To learn more about conservative model. Click, brainly.com/question/14025877

#SPJ4

3 0
1 year ago
Tommy and teagan are learning the process of good home gardening and decide to help their parents as best as they can. every day
Orlov [11]
According to a source, the answer to this question is by compacting the soil, decreasing aeration and infiltration. With this process in mind, the plant would be able to survive.

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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3 years ago
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