A triangle has a base of 3 2/5 inches and an area of 5 1/10 square inches. Find the height of the triangle.

There are 5 times as many males as females on the maths course at university. What fraction of the course are female?

Valentin [98]

Answer:

1/5 are females i think

Step-by-step explanation:

4 0

3 years ago

I need the answer for my homework

sergij07 [2.7K]

Answer:

45 for 5 and 34 for 6.

Step-by-step explanation:

You are just subtracting by 11.

7 0

3 years ago

A manufacturer produces crankshafts for an automobile engine. the crankshafts wear after 100,000 miles (0.0001 inch) is of inter

Daniel [21]

Part A:

Significant level:

α = 0.05

Null and alternative hypothesis:

h0 : μ = 3 vs h1: μ ≠ 3

Test statistics:

$z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}} \\ \\ = \frac{2.78-3}{0.9/\sqrt{15}} \\ \\ = \frac{-0.22}{0.2324} =-0.9467$

P-value:

P(-0.9467) = 0.1719

Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438

Conclusion:

Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.

Part B:

The power of the test is given by:

$\beta=\phi\left(Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) \\ \\ =\phi\left(1.96+ \frac{-0.25}{0.2324} \right)-\phi\left(-1.96+ \frac{-0.25}{0.2324} \right)=\phi(0.8842)-\phi(-3.0358) \\ \\ =0.8117-0.0012=0.8105$

Therefore, the power of the test if μ = 3.25 is 0.8105.

Part C:

The sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:

$1-0.9=\phi\left(Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) \\ \\ \Rightarrow0.1=\phi\left(1.96+ \frac{-0.75}{0.9/\sqrt{n}}\right)-\phi\left(-1.96+ \frac{-0.75}{0.9/\sqrt{n}} \right) \\ \\ =\phi\left(1.96+(-3.2415)\right)-\phi\left(1.96+(-3.2415)\right) \\ \\ \Rightarrow\frac{-0.75}{0.9/\sqrt{n}}=-3.2415 \\ \\ \Rightarrow\frac{0.9}{\sqrt{n}}=\frac{-0.75}{-3.2415}=0.2314 \\ \\ \Rightarrow\sqrt{n}=\frac{0.9}{0.2314}=3.8898$

$\Rightarrow n=(3.8898)^2=15.13$

Therefore, the sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.

8 0

3 years ago

Camila ubicó 90 botellas en una estantería de un supermercado y de ellas eran de jugo sin azúcar.Si los jugos sin azúcar tienen

Tom [10]

Camila puso 30 botellas de cada sabor en la estantería.

Dado que Camila ubicó 90 botellas en una estantería de un supermercado, y los jugos sin azúcar tienen tres sabores diferentes y Camila puso la misma cantidad de cada sabor en la estantería, para determinar la cantidad de botellas de jugo sin azúcar de cada sabor que puso Camila en la estantería se debe realizar el siguiente cálculo:

90/3 = X
30 = X

Por lo tanto, Camila puso 30 botellas de cada sabor en la estantería.

Aprende más en brainly.com/question/16991787

3 0

2 years ago

I need help on this ._.

EastWind [94]

Answer: 40

Step-by-step explanation:

16 + 24

= 8(2) + 8(3)

= 8(2 + 3)

= 8(5)

=40

7 0

3 years ago