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m_a_m_a [10]
3 years ago
7

Please need help on 2 math questions

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Question 1:

For this case we have the following expression:

\frac {\frac {y-1} {y ^ 2-36}} {\frac {1-7y} {y + 6}} =\\\frac {(7y-1) (y + 6)} {(y ^ 2-36) (1-7y)} =

We have to:

y ^ 2-36 = (y + 6) (y-6)

Rewriting:

\frac {(7y-1) (y + 6)} {(y + 6) (y-6) (1-7y)} =\\\frac {7y-1} {(y-6) (1-7y)} =

We take common factor "-" in the denominator:

\frac {7y-1} {(y-6) * - (- 1 + 7y)} =\\\frac {7y-1} {- (y-6) * (7y-1)} =\\- \frac {1} {(y-6)}

ANswer:

- \frac {1} {(y-6)}

Question 2:

For this case we must simplify the following expression:

(3n ^ 4 + 1) + (- 8n ^ 4 + 3) - (- 8n ^ 4 + 2) =

We eliminate parentheses keeping in mind that:

+ * - = -\\- * - = +\\3n ^ 4 + 1-8n ^ 4 + 3 + 8n ^ 4-2 =

We add similar terms:

3n ^ 4-8n ^ 4 + 8n ^ 4 + 1 + 3-2 =\\3n ^ 4 + 2

Answer:

3n ^ 4 + 2

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