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1. Solve for the area of the figure below.

wariber [46]

Answer:

39

Step-by-step explanation:

7 0

2 years ago

Which table represents the function f(x) = 6x - 8<br><br> HURRY PLEASEE

alexira [117]

Answer:

C

Step-by-step explanation:

I did the math

Substitute x for whatever number is on the graph for x then do the math and get the answer for y and see if they are correct for each one.

4 0

3 years ago

Find the area of the rhombus in m squared

Nataly [62]

Answer:

$\boxed{\bold{100 \ m^2}}$

Step By Step Explanation:

Area Of Rhombus: $\bold{\frac{pq}{2} }$

Identify 'p'

5 + 5 = 10

p = 10

Identify 'q'

10 + 10 = 20

q = 20

$\bold{10 \ \cdot\ \ 20 \ = \ 200}$

$\bold{200 \ \div \ 2 \ = \ 100}$

➤ $\boxed{\bold{Mordancy}}$

4 0

2 years ago

At a amusement ,park 360 visitors rode the roller coaster in 3 hours.Write and solve a proportion to find the number of visitors

Pachacha [2.7K]

First you need to find out about how many people went on the roller coaster in one hour by doing 360 divided by 3 and you would get 120. So then you would try to find out how many people went on the coaster in 7 hours by doing 360 times 2 because 3 hours multiplied by 2 is 6 and you would do that to find out how many people went on the coaster in 6 hours, and you would get 720. Next, you have 1 more round of people, so you need to do 720 + 120 which is 840. So about 840 people rode the coaster in 7 hours. Hope this helped.

6 0

3 years ago

Sulfur compounds cause "off-odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compoun

aev [14]

Answer:

a) $29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

b) $z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

$p_v =P(z>1.988)=0.0234$

If we compare the p value and the significance level given $\alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". 
The margin of error is the range of values below and above the sample statistic in a confidence interval. 
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". 
Part a
Data given: 30 30 42 35 22 33 31 29 19 23
We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4$ the sample mean

$\mu$ population mean (variable of interest)

$\sigma=7$ represent the population standard deviation

n=10 represent the sample size

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

Part b

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 25$

Alternative hypothesis : $\mu>25$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:

$p_v =P(z>1.988)=0.0234$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

8 0

3 years ago

Please help me! I need the anwser asap​

Please help me! I need the anwser asap