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3 years ago

E.G IF I WAS BORN IN 1993 WHAT AGE WOULD I BE RIGHT NOW

Mathematics

1 answer:

nataly862011 [7]3 years ago

3 0

About 19 because it ise 2012 and grumpy cat is o a good memsen

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Evaluate. Be smart, <br>(2.31∙5.82+4.18∙2.31+90∙2.31)÷2.31∙0.55

OverLord2011 [107]

= 2.31(5.82+4.18+90)/ 2.31*0.55
=2.31*100/ 2.31* 0.55
=1*100*0.55
=100*0.55
=55

4 0

3 years ago

Expression written using exponents

Scilla [17]

Since there are no specific requirements given other than expression written using exponents, I am just going to give some examples.

1. 5x^2 - 3

2. 8^5 - 15x + 7

3. 15x^10 - 8x^7 + 16x^5 + 17^3 - 4^2 +13x - 2

5 0

3 years ago

Which best describes the relationship between the line that

LUCKY_DIMON [66]

Same line so the correct answer is b

5 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

3 years ago

Q. A customer wants to re-carpet a living room andhallway. You charge $5.99 per square yard toremove old carpet and $4.50 per sq

Tanzania [10]

Living Room Area = 17.5 x 20 = 350 sq ft

Hall Area = 4 x 12 = 48 sq. ft.

Total area of carpeting: 340 + 48 = 398 sq. ft.

We need to convert total area in sq ft to sq yd. The conversion ratio is

1 sq ft = 0.11 sq yd

So, 398 sq ft would be:

398 * 0.11 = 44.22 sq yd.

Carpet removing rate is 5.99 per sq yd.

Removing rate would be:

44.22 * 5.99 = $264.88

Assuming you gotta install both carpet and pad,

Carpet + pad = 16.99 + 3 = 19.99 per sq yd.

You gotta buy for 44.22 sq yd.

So, it will cost (carpet):

44.22 * 19.99 = $883.96

Installing rate 4.50 per sq yrd, so to carpet 44.22 sq yd, would need:

4.50*44.22 = $198.99

Assuming carpet is provided by installation guys, total charge:

4 0

1 year ago