We can rewrite the asked question like this:

wherein X_1 and X_2 are random variable with the same given normal distribution. Then mean of

is zero and the variance
can be computed like this:

So, the random variable

follows a normal distribution
with means 0 and standard deviation 9.6.
The median of the law N(0,9.6) is 0.
So the expected difference of the score is 0.
Answer:
Step-by-step explanation:
distance PQ=√[(0-0)²+(2+11)²]=√13²=13
distance AB=√[(-3-0)²+(-4-0)²]=√(9+16)=√25=√5
distance CD=√[(0-8)²+(-6-0)²]=√(64+36)=√100=10
Ax-a>2
x-1<-1
ok, in the first one, we can undistribute the a
ax-a>2
a(x-1)>2
and we known that x-1<-1, so x-1 is negative
we can assign c for x-1 to do c<-1 then
a(c)>2
ac>2
so if c is negative, then therefor a must also be negve to produce greater than 2
hmm, we see 2 choices that work, B and D
hmm, if c=-1.5
then a has to be 0.75
that is a possible solution so therefor B is false
the answer is D
Answer:
a . 45
Step-by-step explanation:
you can see the 20 is that small so you need to put 1/2 more of the 20 degrees angle to get the equation