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Anna [14]
2 years ago
13

Which is the most accurate way to estimate 50% of 41?

Mathematics
2 answers:
sasho [114]2 years ago
5 0

Answer:

The easiest way is to round down to 40 and take 50% of that, which is 20. The actual answer is 20.5.

Step-by-step explanation:

svlad2 [7]2 years ago
3 0

Answer:

20.5

Step-by-step explanation:

Divide 41 by 2 and get 20.5

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Pls help I'll follow
liraira [26]
The first thing you need to know is f is the greatest common factor 
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5x^2+8x^3+1
another one 
2z^3-y^2+6
hope this helps 
5 0
3 years ago
When ms. shreve solved an equation in class, she checked her solution and found that it did not make the equation true! Examine
Alex777 [14]
The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
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x=7
6 0
3 years ago
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jasenka [17]
Simplified it should be 4x^10y^8
3 0
3 years ago
given y&gt;0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
In a one-tail test, the p-value is found to be equal to .068. If the test had been two-tail, the p-value would have been
devlian [24]

Answer:

The p-value for two-tailed test is 0.136

Step-by-step explanation:

Given;

one-tail test, p-value = 0.068,

In one-tailed test, we test for the possibility of a relationship in one direction and completely disregard the possibility of a relationship in the other direction.

One-tail test provides possibility of an outcome in one direction, while

two-tail test provides possibility of an outcome in two different directions.

Thus, the p-value for two-tailed test = 2 x 0.068 = 0.136

3 0
2 years ago
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